-7x^2+15x-1=0

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Solution for -7x^2+15x-1=0 equation: 



-7x^2+15x-1=0

a = -7; b = 15; c = -1;
Δ = b2-4ac
Δ = 152-4·(-7)·(-1)
Δ = 197
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{197}}{2*-7}=\frac{-15-\sqrt{197}}{-14}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{197}}{2*-7}=\frac{-15+\sqrt{197}}{-14}
$

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